A Chemist Has a Solution of 65

Up to 25 cash back A chemist needs 60 milliliters of a 45 solution but has only 35 and 65 solutions available. The chemist must drain 78 g of the 25 acid.

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A chemist has a solution that is 40 acid and another solution that is 90 acid.

. A chemist has a solution of 65 pure acid and another solution of 30 pure acid. X mL of the 40 acid solution. A chemist has three different acid solutions.

Well we know that 03 X. Find how many milliliters of each that should be mixed to get the desired solution. A chemist has 30 and 50 solutions of acid available.

How many gallons of each will make 350 gallons of 55. Okay so these are these are the volumes that we have. Solution contains 20 acid the second contains 35 and the third contains 65.

He wants to use all three solutions to obtain a mixture of 126 liters containing 30 acid using 22 times as much of the 65 solution as the 35 solution. A Chemist has 100g of 25 acid solution. How many liters of each should she mix to get 1750 liters of a hydrochloric acid solution with a 65 acid concentration.

Theresa Morgan a chemist has a 20 hydrochloric acid solution and a 70 hydrochloric acid solution. Solution for A chemist needs 60 milliliters of a solution that is 45 acid but has only 35 and 65 solutions available. How much of these solution he needs to drain and replace with 70 acid solution to obtain 100g of 60 acid solution.

Answer provided by our tutors Let. A chemist needs 60 milliliters of a bartleby close Start your trial now. _____ liters of 70 hydrochloric acid.

Algebra - Customizable Word Problem Solvers - Mixtures - SOLUTION. Let x the mass of 25 acid the chemist must drain. Solve the problemA chemist needs 70 milliliters of a 65 solution but has only 59 and 73 solutions available.

10 ml of 65 2 Solve the equation. Up to 25 cash back 4 x - 65 x 1 - 13 -25 x -3 x 12 Since we wanted x to represent the number of liters of the 40 acid solution we will then use 08 liters of the 65 acid solution. So then what do we know.

This problem has been solved. Adrianna O CHEMICAL REACTIONS Using molarity to find solute moles and solution volume A chemist adds 4800 mL of a 000348M calcium sulfate CaSO4 solution to a reaction flask. Liters of 30 acid liters of 50 acid.

20 ml of 35. How many gallons of each should be mixed together to get 120 gallons of a solution that is 50 acid. Y Because 65 as a decimal 65 is going to be equal to The 40.

Just taking percent solution times the volume of the total volume. ______ liters of 20 hydrochloric acid solution. A chemist has 30 and 50 solutions of acid available.

40 ml of 65 10 ml of 35. How many liters of each solution should be used. Then x the mass of 70 acid and 100 - x the mass of 25 acid remaining.

How many milliliters of each should be Answered. First week only 499arrow_forward bartleby learn write tutor study resourcesexpand_more. Lets check the answers in our original equation.

How many liters of each solution should be mixed to obtain 65 liters of 34 acid solution. 04 times the 14 leaders. And why for the 65 solution.

20 ml of 65 50 ml of 35. Find how many milliliters of each that should be. How many liters of each solution should be mixed to obtain 65 liters of 34 acid solution.

Because 30 as a decimal is 03 was 065. Calculate the millimoles of calcium sulfate the chemist has added to the flask. A chemist has one solution that is 20 acid and a second that is 65 acid.

A chemist has one solution that is 20 acid and a second that is 65 acid. He wants to make 100 mL of a 70 acid solution how many mL of each solution should he use. 50 ml of 65 40 ml of 35.

Amount of the 70 solution --- x L amount of the 45 solution--- 300-x L70x 45300-x 65300 time 100 70x 45300-x 65300 70x 13500 - 45x 19500 25x 6000 x 240 So 240 L of the 70 stuff and 60 L of the 45 stuff check7240 4560 19565300 195 looks good to me.

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